# Are the leptons in $\beta^-$ decay already present in the nucleus in some form?

In beta minus decay, beta-minus particle and anti-neutrino are ejected, leaving behind daughter nucleus. $\beta^-$ and anti-neutrino both are leptons.

1. Were the leptons already present in the nucleus in some form?
2. Weak interactions are responsible for various processes here (and transformation of bosons).But, anyhow, if the above leptons are created, then can we call leptons elementary & indivisible?
3. Are above leptons mass equivalent of some released energy?
4. Is the transformation of quarks (neutron to proton conversion) and bosons ($W^+,W^-,Z$) the only cause of creation of above leptons? ...SIMILAR process for beta-minus and plus decay. Only neutron-proton conversion opposite, there's positron instead of electron, neutrino instead of anti-neutrino. My question about creation of leptons remains the same.
• What's a $\beta^-$ particle? – pfnuesel Jan 25 '16 at 15:48
• it may be electron or positron – user46925 Jan 25 '16 at 15:49
• No, its an electron (note the superscript -_. – Lewis Miller Jan 25 '16 at 16:10
• SIMILAR process for beta-minus and plus decay. Only neutron-proton conversion opposite, there's positron instead of electron, neutrino instead of anti-neutrino. My question about creation of leptons remains the same. – HEU Jan 25 '16 at 16:21
• all "decay"s ( bad word ) are possible if merely the reactions respect the conservations and the exclusions rules – user46925 Jan 25 '16 at 16:32