# Finding Velocity and Displacement from Acceleration [closed]

First time posting, so please advise if and where I'm braking protocols. Here is the question I was given:

A particle travels with acceleration given by $a(t)=(2e^{-t})i+(5\cos{t})j-(3\sin{t})k$. When the particle is located at $(1,-3,2)$ at time $t=0$ and is moving with a velocity given by $v(t)=4i-3j+2k$, find the velocity and displacement of the particle at any time $t>0$.

I know the relation between velocity and acceleration is $a(t)=dv/dt$, and displacement is the integral of $v(t)$ across an interval. But I'm not sure how to set this one up. Wouldn't the velocity just be the integral of acceleration? And then the displacement is the integral of the velocity? But why then was I given the position and velocity at $t=0$?

## closed as off-topic by Daniel Griscom, Sebastian Riese, user36790, John Rennie, Kyle KanosJan 24 '16 at 10:52

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