I have a question about the forces on a body at equilibrium. Look to this image:
here i draw a man standing with a pen on earth. And I think that I draw all possible forces on it. They are as follows:
1) Force $F_1$ due to the weight of pen.
2) Force $F_2$ acting on earth by pen accourding to newton's third law.
3) Force $F_3$ due to friction between hand and pen to hold it.
4) Force $F_4$ equal and opposite to $F_3$ acting on man.
(Note that magnitude of $F_1=F_2=F_3=F_4$ ).
5) weight of man $W$ acting downward.
6) Since $F_4$ acting on the man downward, the normal reaction is $W+F_4$ acting upward.
I think that I mention every forces here. Due to the fact that the body in equilibrium, all forces must cancel each other. But there comes an extra component equal to the weight of pen. Where is my mistake?