This is my first question here so I hope I get warmly welcomed by answers that would resolve this perplexion :-)
This is a statics problem from Hibbeler's Mechanics for Engineers: Statics (13th Edition)... I have access to its solution from the solution manual, but there is something I don't understand here:
How is AC here a two-force member (as the ISM says) when it has that 2-kN load acting on it at pin A?
When AC is a two-force member, Ax = Cx, and Ay = Cy, then the FBD of member AC would have only the reaction forces at the two pins A and C, how is it that the 2-kN force is not considered here?
I know both questions seem quite similar, but this is for the purpose of clarification as to where the confusion lies.