Physics Stack Exchange is a question and answer site for active researchers, academics and students of physics. It only takes a minute to sign up.
Sign up to join this community
In Newtonian Physics there is an equation that for the Gravitational Flux of an object known as Gauss's Law For Gravity. Gauss's Law for Gravity describes the number of Gravitational Field Lines coming from an object with mass.
Is there something similar to Gauss's Law For Gravity in General Relativity? Is there an equation similar to Gauss's law for Gravity in General Relativity?
There is no perfect analogue because gravitational flux is not a (common) feature of GR.
Recall that Gauss' integral law $$\oint_{\partial V} \mathbf{g}\cdot\mathrm{d}\mathbf{A}=-4\pi G\underbrace{\int_V\rho\,\mathrm{d}V}_M$$ is just the differential law $$\operatorname{div}\mathbf{g}=-4\pi G\rho$$ integrated + the divergence theorem. So the two are equivalent.
Now, there is a pretty good analogue for the differential law in GR, namely the Einstein equations. It is well known that the time-time component of the Einstein equations reduces to the Poisson equation $\Delta\phi=4\pi G\rho$ for "nearly Newtonian" spacetimes. (The Poisson equation is equivalent to Gauss' law because $\mathbf{g}=-\operatorname{grad}\phi$.)
But it is not so simple to integrate the Einstein equations and get an integral law.
For asymptotically flat spacetimes, we have the ADM momentum equation $$P^\mu=\int_\Sigma\sqrt{-g}\star [g^{\mu\sigma}(T_{\sigma\nu}+t_{\text{LL}\sigma\nu})\theta^\nu]$$ (Here $\Sigma$ is a spacelike hypersurface, $\star$ is the Hodge dual, $T$ is the energy-momentum tensor, $t_{\text{LL}}$ is the Landau-Lifsitz pseudotensor and $\theta^\mu$ is a dual tetrad.) The time component of this equation gives the "mass" of the spacetime, like the RHS of Gauss' law above. For for details, cf. e.g. N. Straumann, General Relativity (2013).
Birkhoff's_theorem is sometimes called the relativistic analogue to Gauss's Law, because it says that only the interior energy density effects the local gravitation. ( see Lindesay: Foundations of Quantum Gravity, Grupen: Astroparticle Physics)
There is an analogue to Gauss' law for gravity in general relativity, which applies to stationary space-times, which admit a one-parameter group of isometries with timelike Killing vector whose orbits are diffeomorphic to $\mathbb R$ and span the manifold. In such a case, the metric is,
$$ds^2 = -\psi^2(dt + a_i dx^i)^2 + g_{ij}dx^i dx^j.$$
One then has that the flux at infinity of $\mathrm{grad} \, \psi$, which we denote $\Phi$, is given by the integral,
$$\Phi = \lim_{\rho\to\infty}\int_M \psi \rho^t_t \, \sqrt{|g|} \, d^4x$$
assuming a source $\rho$ and furthermore that the space-time is asymptotically Euclidean. This can be derived by looking at the $(t,t)$ component of the Einstein field equations.
Yes, and relativistic gravity neatly explains Gauss's law.
The simple way to think of gravity resulting from spacetime curvature is: a 3 dimensional volume of space containing mass M expands over time at a volume acceleration of 4πGM. That's essentially a relativistic re-expression of Gauss's Law where instead of describing a gravitational field it describes the deformation of space itself.
For example: for earth, 4πGM is 5M cubic kilometers/sec/sec, so the apparent acceleration of gravity at earth's surface is that rate divided by earth's surface area of 510M square kilometers. The quotient is 9.8 m/s/s, so objects near earth's surface appear to accelerate downward at that rate, 1g. (Accelerometers show the earth's surface actually accelerates upward, as if its volume was expanding at that rate, while "falling" objects nearby have no forces on them and aren't really accelerating - confirming Einstein's 'elevator' epiphany that gravity is a fictitious force.)
Thus relativistic spacetime curvature uncovers the true meaning of Gauss's Law of Gravity and explains Newton's Inverse Square Law. You can find details here.
