from a classical perspective, what is it about angular momentum fundamentally that means it has to be conserved? Surely if I have a rod about a fixed axis and a moving particle hits the end it will cause the rod to spin and therefore create angular momentum? (The particle isn't spinning around a point after the collision!!)
Surely if I have a rod about a fixed axis and a moving particle hits the end it will cause the rod to spin and therefore create angular momentum?
First off, there is no reason to expect that any of the conservation laws apply to the rod. A moving particle collides with the rod, and the rod has constraints that act on it to keep one end fixed. The collision and those constraint forces are external forces, some of which result in external torques. The conservation laws don't apply to the rod. They apply to the rod+particle+Earth system.
- A system conserves energy if there is no transfer of energy between the system and the surrounding environment.
- A system conserves linear momentum if no external forces act on the system and if all forces internal to the system obey the weak form of Newton's third law.
- A system conserves angular momentum if no external torques act on the system and if all forces internal to the system obey the weak form of Newton's third law.
Secondly, you are ignoring that even point masses can have non-zero angular momentum. Angular momentum is always measured with respect to a point, not an axis. The angular momentum of a point mass is easily computed: It is $\vec L = m \vec r \times \vec v$, where $m$ is the mass of the point mass, $\vec r$ is the displacement vector from the central point to the point mass, and $\vec v$ is the velocity of the point mass. When viewed from the right perspective, the rod+particle system does conserve angular momentum. This "right perspective" is one in which the constraint forces on the rod exert zero torque.
Angular momentum is conserved in any system which has no external torques exerted upon it (much as linear momentum is conserved in any system which has not external forces exerted upon it).
The example of a moving particle hitting something and changing that somethings angular momentum is not relevant, since the something doesn't constitute a closed system in that case.
Your example fails to hold for the same reason that "hitting a golf ball means that linear momentum isn't conserved" does.
The contexts I have seen conserved quantities in is for holonomic systems whose legendre transformed variables of the lagrangian have some kind of nice property when it comes to the time derivative. Sometimes they look like some kind of lagrangian multiplier, but in the context of variational calculus. Usually Noether's theorem is quoted but I have never seen enough details of it to know what that means.
Angular momentum is conserved if the system behaves the same way regardless of it's orientation is space i.e its lagrangian is rotationally symmetric.
So if a system isn't sensitive to any rotation, then the angular momentum will be conserved.
protected by Qmechanic♦ Dec 2 '15 at 23:38
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