# Bonding Two Cationic Hydrogen Isotopes (protium) yields H2 or He?

If you have two hydrogen atoms. And they are the isotope form "Protium" (1 neutron removed) and they are also cationized +1 (1 electron removed) then you have (in a sense) a single proton (two of them actually).

1) Are these protons just subatomic particles now (i.e. protons)? Or are they still "Atoms" consisting of only a proton?

2) If you were to bond them, would you have a weird cationized isotope form of H2 or would you have a weird cationized isotope form of He

I would imagine the bond has the 2 protons close to each other, but they are not close enough to have a "strong nuclear force" and thefore are just bonded, not fused, and are technically H2 and only become He when they get close enough to be classified as a Nucleus?

• He$^{^2}$ is not stable - it very rapidly decays to two protons. – Jon Custer Nov 21 '15 at 22:45
• "and thefore are just bonded, not fused, and are technically $\mathrm{H_2}$" does not correspond to any physical reality. W/o at least one electron no bonding MO can be formed. 2 protons are fused into $\mathrm{He^2}$ or they remain just that: 2 protons... – Gert Nov 21 '15 at 23:39
• @Gert so if you had two protiums bonded into H2 isotope (with electrons) and then you cationized it, it would just become 2 protons? – Albert Renshaw Nov 22 '15 at 1:09
• @AlbertRenshaw: I think you're confusing isotopes and molecules. $\mathrm{He^{2}}$ is an (unstable) isotope, obtained by fusion of 2 protons. $\mathrm{H_2}$ is a molecule of diprotium, obtained by chemical reaction between 2 protium atoms. – Gert Nov 22 '15 at 1:21