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Question:-

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My attempt: Since the P block is given a velocity v in the downward direction, the Q block will move in the opposite direction(upwards) with the same velocity v. When the P block collides with the ground, the Q block will have to stop as well and right after that instant P block will move rebound and move upwards and Q downwards. So the answer has to be (c). But the book says that the answer is (a). Thanks in advance.

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As Q had upward motion with velocity v, it keeps on moving up due to inertia of motion at that instant when P had striked and rebounded.May be due to elastic collision P moves up with v velocity.

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