1
$\begingroup$

Suppose I have a wavefunction which collapses to a certain eigenstate after a measurement of energy. In that state, I perform a calculation of position and obtain a certain position value, say $x_0$. After some time, if I perform a calculation of position again, will I obtain $x_0$ again, or will it be something different?

What I have learnt is that, if on performing a calculation of energy, the wavefunction collapses, then a calculation on the collapsed wavefunction will give the same energy, at any time later and for any observer. Does the same hold true for any observable?

$\endgroup$
2
$\begingroup$

You can have a repeatable measurement process (i.e. a measurement process that, roughly speaking, gives the same result if done twice in a row) only for discrete observables.

A discrete observable is an observable whose spectrum is purely discrete. So with the Hamiltonian it is possible to have repeated measurements, provided it is a system with purely discrete energy spectrum (for example, the harmonic oscillator has a repeatable measure process; but the free Hamiltonian of an unconfined particle has no repeatable measure process).

The position operator, however, has always a continuous spectrum; therefore it is never possible to have repeatable measurements. You can have a measurement process of course, but even if performed twice in a row it will give two different results. The same is true for the momentum operator (of an unconfined particle) as well.

$\endgroup$
5
$\begingroup$

Energy is a bit of a special case because the eigenfunctions of the Hamiltonian are time independent (assuming a time independent Hamiltonian). So when you make an energy measurement and collapse the system to an eigenfunction of the Hamiltonian it stays there.

However the position operator does not commute with the Hamiltonian so when you measure the position you will leave the system in some superposition of the energy eigenfunctions. This superposition is not time independant so subsequent measurements of position will not return the same value.

This applies to any operator that does not commute with the Hamiltonian.

$\endgroup$
  • $\begingroup$ Well, this point of view is in my opinion a little bit naïve. The OP is asking if the conditional expectation of measuring $x'$ immediately after having measured the position $x$ would be $\delta_{xx'}$. Of course the time evolution "messes things up" for any observable that do not commute with the Hamiltonian, but repeatability of a measurement is something that you would like to have in the sense above (immediately after), and not after the system has evolved. And even instantaneously, a repeatable measurement do not exist for observables with (partly) continuous spectrum. $\endgroup$ – yuggib Nov 18 '15 at 10:59
  • $\begingroup$ @yuggib: Perhaps I have misinterpreted what Tejas is asking or perhaps not. $\endgroup$ – John Rennie Nov 18 '15 at 11:20
  • $\begingroup$ You are giving a sort of "superfluous motivation"; for it is not only the time evolution that makes the repeatability not possible, but already the continuous nature of the position observable. Take the momentum operator (for a free particle). It commutes with the Hamiltonian, nevertheless a repeated measurement of it is not possible. $\endgroup$ – yuggib Nov 18 '15 at 11:28

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.