Relativistic Commutation relation for momentum and position [duplicate]

This question already has an answer here:

We all know that the canonical commutation relation give you

$$[x^i,p_j]=i\hbar~\delta^i_j,\qquad i,j=1,2,3.$$

Is there a relativistic version such as

$$[x^a,p_b]=i\hbar~\delta_b^a,\qquad a,b=0,1,2,3~?$$

If so what is the time operator $x^0$?

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Actually, if the energy of particles is high enough to take relativity into consideration, the concept of particles in quantum mechanics is no longer as valid. For example, the uncertainty relationship $\Delta E \cdot \Delta t \approx \hbar$ and energy-mass relation $E=mc^2$ suggest that there will be new particles created and annihilated in those cases. So physicists developed quantum field theory to describe the quantum theory in relativistic case. For an introduction course for QFT, maybe you can click here to view the lecture of Professor David Tong.