# If I lick a 9V battery, why doesn't my tongue noticeably get hotter?

Power dissipated is I^2*R, I don't know the resistance of my tongue so I can't tell how much current goes through my tongue. A resistor I have does get hot and I'm guessing it has a higher resistance than my tongue which I'm guessing is very good at conducting since it's wet.

So is it because my tongue doesn't have a lot of resistance that it doesn't get as hot? But if my tongue has higher resistance than I should get a higher current which should heat it up more no?

• ...why would a higher resistence mean higher current? Just use $V = RI$ to get $V^2/R$ for the power dissipated in terms of voltage. – ACuriousMind Nov 1 '15 at 1:57