Hydrogen atom nodes and Bohmian trajectories Wouldn't the fact that the solutions to the hydrogen atom orbital shape have nodes prove that the Bohmian interpretation is incorrect, since in that interpretation, the electrons would have a fixed trajectory, and that would mean we can sample it being in one of those nodes, while passing from one probability 'blob' to another?
 A: No. The nodes are located where there is no probability density so you don't see the particle there. You don't see it in the lab, and you don't see it in Bohmian Mechanics.
It is a mystery why you would think they are there. I'm sure you've read the Bohmian mechanics makes the same predictions. And you know the equation for the how the particle moves and it doesn't move into a node.
So why would you say it does when you know it doesn't? You don't need a particle to move. Keep in mind that where you think there might be kinetic energy there can be quantum potential energy instead. And keep in mind that if your wave is all real, for instance, then there is no motion of the particle so the quantum potential in that state has an equal and opposite gradient as the classical potential at every point. This is fine.

Wouldn't the particle move between the anti-nodes? And when it does so, wouldn't it have a chance of being found in the nodal region between the anti-nodes?

Keep in mind that the probabilistic distribution happens across preparing many instances of the state. It isn't a time average of one state. The particle doesn't move around and spend more time at more probable locations. It is more likely to be put somewhere when the state was prepared, and then only if there is a spatial phase gradient does it move in time after the state is made.
So if you have nodes at a certain radius it starts in one of the regions and then stays there. And this is fine since the probability of starting in each region was correct.
