Wick rotation and spinors I am quite familiar with use of Wick rotations in QFT, but one thing annoys me: let's say we perform it for treating more conveniently (ie. making converge) a functional integral containing spinors; when we perform this Wick rotation, in a way we change the metric to $(-,+,+,+)$ to $(+,+,+,+)$, so the invariant group is no more $SO(3,1)$ but $SO(4)$ and ($SO(4)$ being compact and the spinor representation non unitary) spinors don't carry finite dimensional representation of this group. So I feel like we shouldn't be talking anymore about this objects, but only about vectors of $SO(4)$.
Is my fear justified? or where am I wrong in my reasoning?
 A: I don't think I follow your statement:

spinors don't carry finite dimensional representation of this group.

I follow up in this comment to the original question.
But perhaps a more practical answer to your concern is that usually when you are doing a loop integral in quantum field theory, the object that you are integrating is a scalar quantity---it's the square of a matrix element. So any spinors inside the expression have contracted with other spinors (with some objects like momenta dotted into $\gamma$/Pauli matrices sandwiched inside).
A: When I studied at first course and investigated the special theory of relativity the lecturer said about old interpretation of relativity. In this approach instead pseudo-euclidean metric and four-vectors $(t,\bf x) $ people use  euclidean metric and four-vectors $(it,\bf{x})$. But it does not mean that we use SO(4) group! We use also SO(3,1) group but we do some change of variables.
The Wick rotations is the same thing, it is only change of variables no more.
