0
$\begingroup$

Why time of flight remains same for a projectile even though collision takes place ?

Suppose a ball is projected with some velocity V with some angle θ the the time of flight is T.

Now if another ball is projected with same angle θ and same velocity V then why time of flight is constant?

enter image description here

$\endgroup$

2 Answers 2

1
$\begingroup$

Time of flight is determined only by the vertical component of velocity - it is the time interval between when the projectile was released ($y=y_0$) and when it reaches the ground ($y_t=0$).

As the collision is with a vertical wall it acts in the horizontal direction (assuming no friction during the short duration of the collision) and so has no effect on the y-velocity of the projectile, so no effect on flight time.

If the collision resulted in an impulse that was not in the horizontal direction, then the y-velocity and thus the flight time would be affected.

$\endgroup$
1
$\begingroup$

If the collision is perfectly elastic then there is no change in the kinetic energy during the collision. If there were a change in the kinetic energy during the collision then the flight times would be different. This is analogous to a ball being thrown and encountering no collision.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.