# Black body in thermal equilibrium

In the answer of an exam said that a black body in thermal equilibrium with it's surroundings won't emit any energy, but I don't really understand why.

My logic is that every object emits electromagnetic radiation because of it's temperature, which is a form of transmission of energy, this happens microscopically because or molecules have a random motion, that is the temperature, so an accelerated charged particle emits electromagnetic radiation as a consequence of the varying $\vec{B}$ and $\vec{E}$, so independently the black body is in thermal equilibrium it will always emit radiation as a consequence of the temperature. The energy radiated minus the energy received is the heat flow, so in thermal equilibrium the radiation emitted must equal the received and then the black body and surroundings wouldn't spontaneously change their temperature.

So my idea was that the same it gives the same as it receives and so it wouldn't be correct to say it doesn't emit anything. Can someone explain what was the failure in my approach.

• It might just be terminological with "emitted energy" referring to net flow. See related thread "Why does the blackbody radiate even at thermal equilibrium?" physics.stackexchange.com/questions/148614/… Commented Oct 3, 2015 at 2:06