# Atmospheric pressure inside a rigid vessel

On a macroscopic scale one can explain the atmospheric pressure by the weight of the column of air over a given small area.

If you enclose this air in rigid vessel (for example by pressing together two Magdeburger hemispheres without evacuating them), the pressure of the air inside of the vessel remains the same as outside the vessel though the air column is not present anymore.

How can one explain this sticking only to the macroscopic/phenemological scale, i.e. avoiding microscopic kinetic gas theory?

The best you can do without reference to kinetic theory is apply the ideal gas law $P = \frac{nRT}{V}$ where $P$ is the pressure, $n$ is the number of moles of gas, $R$ is the ideal gas constant and $V$ is the volume.