Motional emf and induced electric fields A book i am referring to states:
"..When the loop moves toward the magnet,it is the magnetic force which drives the charge to flow.But what causes the induced current in a stationary loop when a magnet moves towards it?A magnetic field cannot exert force on a stationary conductor.Whenever a magnetic field is varying with time, an induced Electric field E is produced in any closed path in matter or empty space" 
Then it goes on to state that this induced emf is non conservative because of a non-zero value of circular integral of E.dl.
So,is the former case of when the loop moves in a stationary magnetic field different?
Is electric field in the loop due to "motional emf" conservative?
And the book also,at one point, expresses electric field due to motional emf as a scalar potetnial gradient. 
However,motional emf does sounds similar to induced emf.
My question is,is E due to motional emf and induced E different or not,and why so?
 A: An EMF from a source is defined as a force per unit charge line integrated about the instantaneous position of a thin wire so for an electromagnetic source:
$$\mathscr E=\oint_{\partial S(t_0)} \left(\vec E + \vec v \times \vec B\right)\cdot d \vec l.$$
Where $S(t_0)$ is a surface enclosed by the wire at time $t=t_0$ and the partial means the boundary, so $\partial S(t_0)$ is the instantaneous path of the wire itself at $t=t_0.$ The $\vec v$ is the velocity of the actual charges. Note this is not necessarily the work done on the charges if the wire is moving since the wire goes in a different direction than the charges go when there is a current.
Now, if the wire is thin and the charge stays in the wire and there are no magnetic charges we get $$-\oint_{\partial S(t_0)} \left(\vec v \times \vec B\right)\cdot d \vec l=\frac{d}{dt}\left.\iint_{\partial S(t)}\vec B(t_0)\cdot \vec n(t)dS(t)\right|_{t=t_0}$$
And regardless of magnetic charges or thin wires or whether charges stay in the wires we always get $$\oint_{\partial S(t_0)} \vec E\cdot d \vec l=\iint_{S(t_0)}\left.-\frac{\partial \vec B(t)}{\partial t}\right|_{t=t_0}\cdot \vec n(t_0)dS(t_0).$$
So combined together we get:
$$\mathscr E=\oint_{\partial S(t_0)} \left(\vec E + \vec v \times \vec B\right)\cdot d \vec l=-\left.\left(\frac{d}{dt}\Phi_B\right)\right|_{t=t_0}$$
The force due to the motion of the wire is purely magnetic, and the force due to the time rate of change of the magnetic field is purely electric. And the work done is an entirely different question than the EMF. The work happens for a motional EMF when a Hall voltage is produced.

So,is the former case of when the loop moves in a stationary magnetic field different?

A moving wire feels a magnetic force and magnetic forces can be a source term in an EMF.

Is electric field in the loop due to "motional emf" conservative? 

Motional EMF is not caused by electric forces, it is caused by magnetic forces. Since magnetic forces depend on velocity, the word conservative does not even apply since the force depends on the velocity, not merely the path, and they don't do work.

And the book also,at one point, expresses electric field due to motional emf as a scalar potetnial gradient.

If the wire develops a Hall voltage due to the magnetic force, then the charge distribution for the Hall voltage would set up an electrostatic force, which is conservative.
In particular, if the magnetic field is not changing, then the electric field is conservative.

However,motional emf does sounds similar to induced emf. 

When you compute the magnetic flux at two times the term $-\vec B \cdot \hat n dA$ can change for two reasons, a changing loop and a time changing magnetic field. You really get both effects from the product rule for derivatives. The one from the time changing magnetic field becomes equal to the circulation of the electric force per unit charge. The one from the time changing loop becomes equal to the circulation of the magnetic force per unit charge.

My question is,is E due to motional emf and induced E different or not,and why so?

The electric field is conservative if the magnetic field is not changing in time. And if the magnetic field is not changing in time, the EMF is due solely to the moving charges in the moving wire interacting with a magnetic field.
A: Let's restate Faraday's Law of Induction carefully in integral form:
$\varepsilon = -\frac{d}{dt} \int_S B \bullet da = - \frac{d \Phi}{dt} $
Where C is a closed curve, and S is any smooth surface whose boundary is C.
So as you can see, no matter how the generation of electric field is interpreted (take the two scenarios in your question), the motional emf $\varepsilon$ is NEVER 0 unless the magnetic flux is not changing. In both of your scenarios, the magnetic flux is changing and in fact at the SAME rate! That is how they produce the same effect.
As Timaeus pointed out, in the case of stationary loop, there seems to be an electric field generated in the loop that drives the current. While in the case of moving loop, the magnetic force does the job. However, these interpretations are two sides of the same coin: relativity. From a relativistic point of view, magnetic fields are really born from principles of relativity + electric field. What is regarded as electrical effect in the stationary loop case transforms into a magnetic effect in the moving loop case. But since the two scenarios in your question are really just a switch between two inertial frames, there shouldn't be any difference in the outcome of the experiments (it would be weird if there were... Einstein would be shocked out of his grave). From that perspective it is also clear that the emf $\varepsilon$ should be the same in both scenarios.
So motional emf and induced emf are really just two descriptions of the same effect which is summarized by Faraday's law of induction. The fact that two views give the same result is a manifestation of the relativistic nature of magnetic fields.
For more information on deriving magnetism from electricity, and on field transformation laws, I refer you to chapters 5 and 6 of Edward Purcell's E and M textbook: http://www.amazon.com/Electricity-Magnetism-Edward-M-Purcell/dp/1107014026/ref=sr_1_2?ie=UTF8&qid=1443095756&sr=8-2&keywords=purcell+e+and+m
