In a quantum book I am reading for self-study it is noted that the magnetic dipole moment of the $^3$Li$^7$ nucleus can be calculated as

$\mu = 1.67 \times 10^{-26} J\cdot T^{-1}.$

However there is not an explanation as to where this figure comes from. It seems like perhaps one should consider the structure of $^3$Li$^7$ in some way as to calculate the magnetic moment in a similar way to the Bohr magnetron? Besides this I'm at a loss here with how to arrive at this value for $\mu$, can anyone please explain where this comes from?

  • $\begingroup$ Possibly relevant; I haven't checked whether you can use an alpha-triton cluster the way I used an alpha-deuteron cluster in that answer. What book? Is there a calculation method described nearby? What methods have you tried? $\endgroup$
    – rob
    Sep 24, 2015 at 3:04
  • $\begingroup$ $$ \mu_{dipole} \approx \frac{e \hbar}{\mu_{mass}} $$ $\endgroup$
    – user97261
    Jun 14, 2016 at 18:09


Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.