Where is the event horizon in a black hole? At the beginning I thought that the event horizon coincides with the surfaces, but then making a new name when you could just call it surface would seem a bit pointless.
Then where is the event horizon? Is it inside or outside the black hole? 
Notice that I have a really basic knowledge about physics
 A: An event horizon is a "sphere-shaped surface of influence" of inescapable gravity from/towards the black hole. It is the point where the object (victim?) cannot overcome the gravity of the black hole, and will be sucked into it. This is also the point where, theoretically, you would vanish to an outside observer, since the light crossing the event horizon also will not escape to bounce back to the observer.
There is not one particular location/altitude for an event horizon, it depends on the size and mass of the black hole. The more the mass, the more the gravity, thus a larger event horizon.
Wikipedia has a nice writeup about them, although this article is more about event horizons in general, not just for black holes.
Edit: I use the term "Sphere of Influence" loosely -- you would enter the sphere of influence (meaning your motion would be affected by the black hole's gravity) before you would cross the event horizon -- you could return from the SOI, but you couldn't return once past the event horizon.
A: The event horizon is not a place.
If it was a place you could stay there. A black hole has an inside and an outside and the event horizon is the boundary between them.
A black hole's event horizon is not the only kind of event horizon. If someone started accelerating to the right at constant acceleration and never stopped accelerating they would have an event horizon. There would be events (an event is defined as a combination of a place and a time, it is a when-where), events they eventually see and events that they would never ever see and the boundary between them is the event horizon.  In this case the event horizon literally moves to the right at the speed of light and that is why when something crosses it it can't cross back.
For a black hole there are observers that stay outside and they share a common event horizon and it acts just like a surface that expands outwards at the speed of light because acceleration and gravity are very similar. What's weird is that it maintains the same size, and has the same surface area. It is like space is accelerating into the black hole and the surface rushes out at the speed if light and they perfectly balance.
But it isn't a place. That said, when you say surface I can't tell which surface you are taking about. The photon sphere (inside it you can't have orbits that don't crash in) the ergospshere (inside it you have to rotate with the star) and the event horizon (the point of no return).
A: I understood what was my doubt, which was a more basic question:
A star has a clear surface, and within the surface it is all mass.
When a black hole is born, for example after a supernova, i couldn't understand if the event horizon contains all the mass like a normal star. Instead from my understanding, the radius of the surface which contains all the mass is much smaller than the radius of the event horizon. 
Of course, we can't say for sure that the the radius of the mass object is smaller than the event horizon, since we can't see what happens within.
So in other words a black hole is by definition much bigger that I thought since I make it coincide with the surface of the mass object.
