4
$\begingroup$

I was reading up on electrostatic particle accelerators when I read a statistic stating the efficiency of converting wall electrical power (the electrical power from the outlet) into beam power in an accelerator. I tried finding out why this was the case and doing some first cut calculations. The most I could come up with was a lot of the power gets wasted by particles not being efficiently collimated, I.E. most of the accelerated particles hit the wall. Now, I'm pretty sure that is not the only reason, I assume depending on the quality of the vacuum, scattering by the leftover gas molecules would also contribute to the lost beam power, as well as losses via emitted radiation from focusing the charged particles with magnetic fields.

Am I getting this right? Or am I missing some huge power draw that sucks most of the power away from the beam? I know the efficiency depends somewhat on the beam maximum energy (since higher energy beams have higher brehmstrahlung and cyclotron radiation losses), I'm looking at the power efficiency of a 10 MeV electrostatic electron beam accelerator.

Why are 10 MeV electron electrostatic particle accelerators so inefficient?

|cite|improve this question
$\endgroup$
  • $\begingroup$ You have to maintain a large electrostatic potential difference, right? What does the circuit that does that look like? How much power does it take to run? Remember to allow for various leakage currents. (Just guessing, BTW, I've never worked it out myself.) $\endgroup$ – dmckee♦ Sep 8 '15 at 2:31
  • 1
    $\begingroup$ Can you cite the source? For the most part electrostatic accelerators have gone out of favor many decades ago. There is no inherent reason why they can't be made reasonably efficient, probably similar to a klystron based AC machine. Beam collimation shouldn't waste much, if any power. UHV is not a problem these days, either. Can you tell us what you want to do with a 10MeV machine that requires efficiency? $\endgroup$ – CuriousOne Sep 8 '15 at 5:12
  • $\begingroup$ Yes, I'm look to see if it can power a free electron laser for converting visible light into gamma rays for transmitting solar energy from near the sun to Earth orbit. The efficiency is needed (at least 30% of visible light energy becomes gamma rays) so that the platform can deliver enough power to be profitable (within a year of operation) $\endgroup$ – user11377 Sep 8 '15 at 6:40
  • $\begingroup$ @CuriousOne - Electrostatic accelerators have fallen out of favor for particle physics, but the ubiquity of SEMs, TEMs, FIBs, ion implanters, and whatnot suggests there are plenty still around. UHV is not a problem, but is not exactly energy efficient. For the poster - very little beam will hit the walls (if run properly). However, for high stability voltage control you have current flowing down a string of high-precision resistors on the column to establish the potential gradient. This has to be a high % of beam current to be effective. Then all the ancillary equipment adds up fast. $\endgroup$ – Jon Custer Sep 8 '15 at 14:07
  • $\begingroup$ @JonCuster: SEMs etc. usually work at energies of 10-200keV and tiny beam currents. Efficiency is of absolutely no concern for their design. The main concern for ultra-high voltage electron microscopes (I am only aware of a few in existence, to begin with) is beam stability. Commercial high energy ion implanters seem to be based on RF linac designs these days. The high beam current, medium beam energy facilities that I am aware of have very reasonable efficiency, within the limits of the technically necessary, of course. The OP still hasn't told us what his application is, though. $\endgroup$ – CuriousOne Sep 8 '15 at 14:41
0
$\begingroup$

As one data point for linac efficiency, I found a nice presentation from a Jefferson Lab meeting (where CEBAF is - Continuous Electron Beam Accelerator Facility). This is from Googling 'energy efficient linac'. In it, they quote that the CEBAF klystrons are about 25-28% efficient, while their new solid state amplifier proposal (an SBIR, can see at Far-Tech, I have no affiliation other than Googling them) is 55% efficient. This is at 1497 MHz, and 6.5kW linear mode amplification.

Now, that ignores efficiencies in the electron source, focusing elements, steering plates, and all the vacuum components (a 300 liter/sec turbo plus backing runs about 700W). It also ignores production of cooling water and so forth, that will contribute to the overall (in)efficiency (and you will need lots of cooling of whatever target you are trying to get gammas out of). We won't even go in to the electron-to-gamma conversion efficiency, much less how you are realistically going to extract energy from the gamma beam on the other end.

|cite|improve this answer
$\endgroup$
  • $\begingroup$ The fact that is hard to transfer power from the wall to the beam is an undisputed fact. The weird point here is that DC is much less efficient than RF... It also sounds a weird comparison to me as their applications are pretty much different. $\endgroup$ – DarioP Sep 16 '15 at 9:24
  • $\begingroup$ I'm not sure that DC is much less efficient than rf as a rule. Part of it is what you mean by efficiency. For example, rf systems are pretty bad on the front end, that is, getting the source ions into the system in the first place (while bunching helps, it is far from 'efficient'). I'd claim a DC accelerator gets more beam power on target per unit power in. But, you won't get 100's of MeV or >GeV beams out of it... $\endgroup$ – Jon Custer Sep 16 '15 at 15:40
  • $\begingroup$ By efficiency I mean what stated in the question: the fraction of wall plug power that ends up into the beam. I think that the question is flawed, after all the OP didn't provide any reference for that. $\endgroup$ – DarioP Sep 16 '15 at 17:52

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.