# Help me understand Gauss law

Suppose I have the following, the gaussian surface is the drawing in the middle. So charge enclosed is zero, and then eletric field must be zero since the area of the gaussian surface is not zero. But, clearly the eletric field is not zero in the middle, because if you put a charge there it will move. Why I'm getting the concept wrongly? Edit: you can consider the middle figure as a sphere. If the charge between the two surfaces is $$0$$ (zero) initially, that makes $${q}/{\epsilon} = 0$$ and Gauss Law states that the Electric Flux is directly proportional to charge inside it, i.e.,
$$\phi = \dfrac{q}{\epsilon} = \displaystyle\oint\vec{E}.\vec{dA}$$ ,
Here $$\vec{E}.\vec{dA}$$ represents the dot product of the differential area and the electric field passing through it.
Even, if the flux is zero, $$\displaystyle\oint\vec{E}.\vec{dA}$$ becomes zero. Only if electric field and its area vector was always parallel i.e., always perpendicular to the surface, then the electric field can be claimed to be $$0$$ (zero).