I understand that you resolve the components of the balls weight parallel and perpendicular to the slope in order to calculate the force due to gravity that actually acts down the slope.
The component parallel to the slope would be: $m g \sin(x)$ Normal to the slope would be: $mg\cos(x)$
cancelling the masses you get the acceleration down the slope to be $g\sin(x)$.
Can you then resolve this acceleration into its horizontal and vertical components? Would you also need to resolve the component normal to the slope once more into horizontal and vertical components if you can do so, and then add them?
Doing the above ( and leaving out the component normal to the slope) I got the vertical and horizontal acceleration to be:
vertical: $g\cos^2(x)$ horizontal: $g\cos(x)\sin(x)$
I want to be able to work out the horizontal and vertical components of the velocity of the ball once it has reached the bottom of the slope, but am not quite sure.
Any help would be greatly appreciated!