# Nuclear decay of V-48

I have a question on the "decay" of Vanadium-48. The reason it's in inverted commas is because I'm not sure whether decay is the right word.

Basically what I'm trying to work out is whether it's likely/possible that I can, via a few steps, get from V-48 to Sc-46.

Is it possible that if I start with a large amount of V-48, this can over time "decay" into V-45? Can Isotopes of elements just lose neutrons and change into other isotopes?

After that I'm hoping that I can follow the natural decay of V-45 into Ti-45 via electron capture, and again via electron capture this goes to Sc-45, which perhaps via Neutron capture could become Sc-46 with gamma emission?

Is my thinking on this completely wrong? Does my question make sense? Appreciate any help or advice, I'm sure it's relatively obvious that I'm no expert.

Many thanks.

According to wikipedia, Vanadium-48 decays via $\beta^+$ (positron emission) to Titanium-48, which is a stable isotope.