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I have a ballpoint pen stand on my desk. The pens are held inside their caps with the point down, like this one (but not as fancy):

credits http://www.engeika.com/product/692

If I try to simply pull up one pen, the friction between cap and pen is strong enough to lift the stand, instead of simply removing the pen from the cap.

But If I spin the pen while pulling, it comes out without even bumping up the stand.

Why spinning the pen reduces the friction against the pull?

Info requested by the commenters:

  1. the cap tip is hollowed. The pen's body is hexagonal. No vacuum is at work here.
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  • $\begingroup$ Is there suction created when not spun? $\endgroup$ – ja72 Jul 30 '15 at 16:05
  • $\begingroup$ @ja72 the cap tip is hollowed. The pen's body is hexagonal, and the volume displaced by the tip inside the cap would not be enough to support the weight of the wooden stand. $\endgroup$ – Mindwin Jul 30 '15 at 20:11
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Actually, spinning the pens bring a relative motion between cap and pen. When the surfaces of two objects are at rest with respect to each other static friction force acts between them and a kinetic friction force acts between then when they are in relative motion.

Static frictional force $>$ kinetic frictional force.

You may want to read about the functioning of frictional force (what happens between the surface at atomic level) in detail to understand the above stated inequality.

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  • $\begingroup$ The stand weighs around 500g with all the office supplies inside. The difference between dynamic and static friction coefficients is not that large to allow me to lift it "without even bumping the stand". $\endgroup$ – Mindwin Jul 30 '15 at 20:26
  • $\begingroup$ @Mindwin you're ignoring the fact that the pen can be "wedged in" to the cap. The cap and pen are slightly elastic, so they deform when you press them together. The cap then is under tension and the pen under compression, which presses them together and greatly increases the coefficient of static friction. Given that such pressing happens any time you place the pen into the base, I'm nit surprised that the pen can lift the base through friction. $\endgroup$ – Asher Jul 31 '15 at 2:11
  • $\begingroup$ @Asher Isn't the friction coefficient material-dependent only? $\endgroup$ – Mindwin Jul 31 '15 at 11:56
  • $\begingroup$ @Mindwin ah yes, I misspoke. The coefficient itself is unchanged, what I meant there is the frictional force, which depends on both the coefficient of friction and the normal force. It is the normal force that is increased by wedging the two together. $\endgroup$ – Asher Jul 31 '15 at 22:08
  • $\begingroup$ @Mindwin @"I am bit surprised that the pen can lift the base through friction"....please think again....that pen can even raise a 1 Kg brick through friction. $\endgroup$ – 23rduser Aug 10 '15 at 12:37
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You are overcoming the static friction, which others have noted is generally greater than dynamic friction. But, the force needed at the point of contact is presumably the same when twisting versus when lifting, so why the difference in the behavior of the stand (lifting up, versus just sitting there)?

The reason is because of the direction the force is applied. Let's say a 250g force is needed to overcome static friction of the pen in the holder. If you pull upward on the pen, then if the holder is lighter than 250g, then you'll lift up the stand rather than remove the pen.

But, let's say you twist the pen hard enough to exert a 250g force on the boundary between the outside of the pen and the inside of the holder. This is applying a torque, and if the torque is strong enough the holder will twist. How strong would the torque be?

Let's say the pen outside and holder inside are 1cm in diameter, and the stand itself is 15cm across. The torque produced by your 250g at the surface of the pen is equivalent to that produced by about 17g at the edge of the holder. If the holder weighs, say, 200g, then trying to twist it with less than a tenth of that force seems likely not to budge it.

Edit: So, now you have the pen spinning; why can you lift it up without still lifting the stand? Because you've already overcome static friction; you only have to add a small vertical force to start removing the pen from the holder.

(Yes, there's a whole lot of "let's say"s in there; if you post actual weights and dimensions I'll get more concrete.)

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This is not a complete answer, but by spinig the pen you give to your system the same energy as if you pull it out directly, in two diffrent forms.So the ''spinning'' energy overcomes the friction and the rest pulls out the pen.

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For the same reason if you try to push a block or your coffee mug placed on the table it take some force before it move but when it starts moving you can lower the amount of force you applied but the block/mug keeps moving.

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protected by Qmechanic♦ Jul 30 '15 at 20:53

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