Considering the molar form of the ideal gas law I can solve for the ratio of some gas volume, $V$ divided by the number of gas particles, $n$ in mols $$\frac{V}{n}=\frac{RT}{P}$$

And $R$ is the Universal Gas Constant

So then if I roughly have 1 mol of gas occupying 22.4 liters of space (the gas 'volume') then I can expect that the temperature, $T$ and pressure, $P$ on the right side of the equation are at the standard values.

Is this interpretation right?

  • $\begingroup$ $T$ and $p$ can both vary here as long as their ratio is constant. $\endgroup$
    – march
    Jun 26, 2015 at 20:19
  • $\begingroup$ @march good point. I suppose then that underlines a fact that 'standard ' temperature and pressure are somewhat an arbitrary choice. But the ratio must be specific. $\endgroup$
    – docscience
    Jun 27, 2015 at 13:26

1 Answer 1


The Title is not matching the description. Answer as per title will be : Yes one can do this but it is usually done the other way. In most of the books first the equation PV=mRT (R is gas constant whose value depend on nature of gas) is established then they use avogadros principle to state it in molar form as PV=(nM)RT ; V/n=MRT/P ; V/n=R'T/P Using avogadros law one can observe that R' is a constant, independent of nature of gas. Thus R'=(MR) is called universal gas constant.


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