Rest Mass and Wigner's Classification I believe (but please correct me if I'm wrong) that I understand the basic philosophy and most of the mathematics involved in Wigner's classification of particles via group representations.  But I'm missing one key bit of physical intuition that I'm hoping someone can provide.
Here's the part I think I understand (feel free to skip this paragraph and the next one if you just want to get to the question):  The state space of a physical system is the projectivization of a Hilbert space $H$.  An element of the Poincare group moves this system to a new location in spacetime and changes its state in some way.  We believe that this should not affect the outcomes of experiments, so the inner product of two state vectors should be unaffected.  Thus the Poincare group acts on the projectivization of $H$ in a way that preserves inner products.  This action lifts to an action of the universal cover of the Poincare group on $H$ itself.  Wigner proves (more or less) that this action must be unitary.  Also, if the physical system is a single particle, it makes sense that the representation should be irreducible.  So to classify particles, we should classify irreducible unitary representations of the universal cover of the Poincare group.
I also (mostly) understand how the classification goes:  We let $SL_2({\mathbb C})$ act on Minkowski space, and find representations of the isotropy groups.  Thus each particle is associated with some orbit, and the orbit is characterized (more or less) by its (Lorentzian) distance from the orign $m$.  For each such orbit, we get a discrete set of irreducible representations (i.e. particles) coming from representations of the isotropy group of a representative point.
Here's what I don't get:  We now identify the (continuous)  parameter $m$ with the particle's rest mass, and the remaining discrete parameter with the particle's spin.  My question is:

Why do we identify $m$ with the rest mass as opposed to some other property of the particle?  

Perhaps the answer is just that $m$ seems to be telling us something about the particle and that rest mass is the only natural candidate that comes to mind.  But I suspect there's a deeper reason, and that I'm missing it.
One could ask an analogous question about the discrete parameter and spin, but mass is easier for me to think about, and at least (in this context) equally mysterious to me, so I'd like to understand that first. 
 A: 
We have a number m that shows up in a purely mathematical context and
  then we interpret it as having a physical meaning. The question is:
  What is the intuition that connects the two?

The intuition connecting the two is essentially identical with the reason why Wigner connects the purely physical notion of an elementary particle with the purely mathematical notion of an irreducible unitary representation of the Poincare group.
For any relativistic quantum system, the total 4-momentum is a 4-vector $P$ whose components are commuting operators. In a common eigenstate of these operators, $P$ becomes a numerical vector, from which one can calculate the total mass $m$ through the formula $(mc)^2=P^2$ (in the +--- metric). In a rest frame, the spatial components vanish, so that $P^2=P_0^2=(E/c)^2$, where $E$ ist the rest energy, giving $E=mc^2$. This is why $m$ is called the rest mass. 
Noether's theorem now says that the 4-vector $P$ is the infinitesimal generator of the group of translation symmetries, which is a subgroup of the Poincare group. Therefore the Poincare group acts in some unitary representation, and $P$ represents the image of the translation group generator in this representation.
For an elementary system (usually referred to as an - elementary - particle) one makes the extra requirement that there is no Poincare invariant subsystem, which translates to irreducibility of the representation. Since $P^2$ is a Casimir operator, it has in any irreducible representation a constant numerical value $M^2$. If this irreducible representation is the representation of an elementary system, we therefore have $M^2=(mc)$^2, which gives $M=mc$. Now in the present context the units are typically chosen such that the speed of light takes the value 1.
Therefore we find that the number $M$ arising in a purely mathematical context has the physical interpretation of a rest mass whenever this representation belongs to that of a particle. 
The same kind of reasoning is applied more generally - whenever a mathematical concept gets a physical label.
A: Usually the first step in deriving the reps of Poincaire is to go to the rest frame of the particle. This amounts to choosing a basis where $P^0$ acting on the state is nonzero, and where the eigenvalue a of $P^i$ are zero. We can do this if the momentum is timelike, that is if the eigenvalue of $P_\mu P^\mu$ is negative (in -+++ signature). Furthermore the sign of the eigenvalue of $P^0$ matters, we'll focus on the positive case. (Note that the irreducible reps are classified but the value of $P_\mu P^\mu$, as well as the Pauli Lubanski operator, because these are casimir operators (commute with all the group generators of Poincaire)--these operators will have the same eigenvalue acting on any state in an irreducible rep). 
Long story short, we've picked a basis/frame where the energy P^0 is positive and the momentum P^i is zero. The energy in the rest frame is the mass. 
Also notice that $P_\mu P^\mu = - m^2$ (eigenvalue of the operator $P^2$ in this irrep) is the on shell condition for a massive particle. 
