# What is the best way to calculate speeds at other points in a venturi-tube when knowing one?

I and a friend have made a venturi tube trough which water flows at a low speed. The flow is therefore laminar. We measured the static pressure using some piëzometers at the points 1,2 and 3. We know the average velocity with which the water flows at the end of reservoir 3.

My friend suggests calculating the speeds at other resvoirs(1,2) of the venturi-tube by using the volumetric flow rate. We namely know the cross-sectional area of the venturi tube at all places.

I however don't think this volumetric flow rate will stay the same because of frictional losses, and so prefer to calculating the speed by using a bernoulli equation with a head loss incorporated in it. What's best to calculate the other speeds in this situation? Or are we both completely wrong?!

Diameter of the venturi tube at different points:

• Point 1: 17 mm
• Point 2: 13 mm
• Point 3: 10 mm Measured static pressure at points:

• Point 1: 106503 Pa
• Point 2: 105375 Pa
• Point 3: 102903 Pa

Measured velocity at the end of reservoir 3:

1.8 m/s

Differences between methods:

• Calculated head loss between the end of reservoir 2 and the end of reservoir 3 : 0.1208901666 Pa

• Calculated velocity at the end of reservoir 2 using bermoulli with head loss: 0.81 m/s

• Calculated velocity at the end of reservoir 2 using constant volumetric flow rate and area changes: 1.06 m/s

• Can you put a value on the frictional losses? – Kyle Kanos Jun 16 '15 at 13:29
• What pressures are you measuring? You can't be measuring the Bernoulli pressure because that falls with velocity so it should be lower at point 1 than point 3. If you're measuring the static pressure then how is that related to the flow rate? The Hagen-Poiseuille equation? – John Rennie Jun 16 '15 at 15:34
• Now that you edited the question, $1.8*(10/13)^2 = 1.06$ should be the velocity at point 2, based on volumetric flow rate. – Mike Dunlavey Jun 17 '15 at 17:25
• @MikeDunlavey You're correct. I have been using the wrong cross-sectional area for calculating the speed at the end of the second reservoir, this is why my original answer was so strange. Thanks for your help. – Ruben23630 Jul 8 '15 at 16:24