Strong force between quarks that are out of causal contact This is a rather artificial scenario, but it has been bugging me lately.
Background
Due to the confinement in QCD, quarks are bound in color-neutral configurations. Any attempt to separate a quark from this bound state costs so much energy that it's enough to pair-produce new quarks, hence the quark-jets in accelerator experiments.
Setup
I'm now considering the reversed (hypothetical) scenario. Assume the you initially have two quarks (up and anti-up for instance) that are placed far away from each other. Buy far I here mean further than any other length scale in CQD.
Now, let the two quarks approach each other, as in a scattering experiment.
Question
At what distance does the two quarks start to interact, and what happens? Since the strong force is confining, the interaction should be stronger the further away the quarks are, but they cannot interact outside of their causal cones, so how does this work at really long distances?
My thoughts
I'm imagining that the "free" quarks are in a metastable state and the true ground state is the one where several pairs of quarks have pair-produced to bind with the two initial quarks. Thus the closer the two initial quarks are, the smaller the energy barrier between the metastable and the true ground state becomes. Thus at some separation $r$ there is a characteristic time-scale before pair-production occurs.
 A: I don't think this assumption is legit:

Assume the you initially have two quarks (up and anti-up for instance)
  that are placed far outside of causal contact with each other

for a real experimental setup.
Indeed, what would have been the previous history of those two scorrelated (outside of each other's light cone) quarks, to be produced isolated?
If, otherwise, you assume this setup, than your question become interesting. 
A: The strong force is similar to electromagnetism (the only difference is the gauge group), and like electromagnetic field lines, strong-force field lines have to originate/terminate where there is charge. Anything else would violate the strong-force version of Maxwell's equations.
In particular, if the universe contains only two quarks, and the field goes to zero at infinity, then there necessarily are field lines connecting the quarks. Of all the possible ways to do this, the lowest energy configuration is a narrow straight flux tube.
If you could somehow produce this configuration, in the next instant it would disintegrate into quark-antiquark pairs, so you would never get a chance to bring the original quarks together. Any other field configuration would have higher energy, so the result would be the same but more so.
If that decay never happened (which is absurdly unlikely but no more unlikely than producing this configuration in the first place), you would simply have a flux tube exerting a constant force of 10,000 N on each quark as usual. The force comes from the local field configuration, not from the other quark.
