# Why charge distribution is greatest at pointy edges of a surface? [duplicate]

If we have a conductor which is in electrostatic equilibrium, then the charge distribution over this surface $\sigma$ is greatest at the sharp edges of that surface.

Why is this the case?

I want both the proof of this result and the intuition behind it.

• @RobJeffries the question you're referring to asks why a non-spherical charge distribution is never uniform, whereas I'm asking why the value of a charge distribution is greatest at sharp edges of the surface, Can you explain how it is a possible duplicate? – Omar Nagib Jun 7 '15 at 22:08