If I understand correctly, an electron volt is the work done when an electron is moved from a plate with a voltage of 0V to another plate with a voltage of +1V. This is represented by $V = W/Q$, or $W = VQ. W = 1$(volt, change from 0 to +1) * $1.6\cdot 10^{-19}$(coulombs, the charge of an electron), which, of course, is $1.6\cdot 10^{-19} J$. The work, the electron volts eV, is this value of $1.6\cdot 10^{-19}$ J.
My question is: how is this accurate? If we use Einstein's $E = mc^2$, we can arrange this to $m = \frac{E}{c^2}$. The energy is our value ($1.6\cdot 10^{-19}$ J) over the speed of light, squared ($299792458 \frac{m}{s}$). This gives us $1.78\cdot 10^{-36} kg$.
However, a quick Google search tells us that the mass of an electron is 9.10938E−31 kg (quite literally 100% wrong with percent error).
My question is, why does this not work out? Is Wikipedia wrong? Is the math wrong? It does seem rather peculiar that the speed of light would be used here, but that's a simple observation.