Why water wave won't diffract or bend around a boat having a length longer than its wavelength? I get the slit version of diffraction, with the Huygen's principle. 
But I don't find the same principle useful.
I keep thinking that a obstacle like a boat is the same as two large slits on both sides. So on this basis, the wave is never gonna diffract.
edit: I am wondering why the length of the wave shown here is so small compared to that of the ship, but yet it diffract?!

2nd edit: Huygen's principle:

 A: The water wave will diffract at the edges , but with respect to the size of the boat it will be like a small shadow.
It is analogous to what happens to water waves going through a slit, demonstrated here at about 2'30", one sees that the shorter the wavelength the more narrow the diffraction pattern.  If the wave length were made very small then it would pass through with only a small dispersion at the edge. If the wave length is very large the slit acts as a point source for the dispersion of energy.
It all depends on how a plane wave reacts to and obstacle. Think of the two limits:
1) if wavelength is very much larger than obstacle, a piece of wood in the water, the wood is essentially a part of the mass of the water that is undergoing the up and down motion, not distinguishable from water and allows the energy to go through without effect.
2)if the wavelength is very small with respect to the obstacle, the part of the wave hitting the obstacle will give up all its energy on the obstacle and be absorbed. Only at the edges there will be a continuation of the plane wave plus an interference from the part of the wave that scattered at the edge, a bit of difraction, which, as the wavelength is small, will be of small extent in the shadow of the obstacle.
