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How to find the period of a simple pendulum in an elevator going up with an acceleration of $a$.

Don't just say, $T=2 \pi$ $\sqrt{ \frac l {g+a}}$

I want to know how the above equation is formed.

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    $\begingroup$ What do you think? $\endgroup$ – CuriousOne Jun 2 '15 at 2:59
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    $\begingroup$ I downvoted this because the answer is on this site and one 10 second search found it. $\endgroup$ – user81619 Jun 2 '15 at 3:11
  • $\begingroup$ I searched you know but couldn't find anything helpful $\endgroup$ – jessij Jun 2 '15 at 3:14
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Einstein's Equivalence Principle (also derivable I believe from Newton's laws) states that being in an accelerating frame of reference is indistinguishable from being under a gravitational force.

In particular, the mechanical laws in an accelerating frame of reference are the same as if a gravitational field of equivalent magnitude were added in the opposite direction to that of the acceleration.

So in your frame of reference accelerating upward at a in a standard gravitational field of g downward, we see that this is equivalent to a gravitational field of (g+a) downward.

So we can take any equation involving the local gravitational field g which applies in an inertial frame, and change g to (g+a), and this new version will apply in your accelerating frame.

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  • $\begingroup$ Can you please, help me in deriving this using Newton's laws? $\endgroup$ – Hisab Sep 22 '17 at 8:42

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