# Do we weigh more when standing near massive buildings?

I'm very new to the concepts of SR/GR and curvature of spacetime.

My understanding is that the bending of spacetime is the causation of gravity, and that matter is the causation of the bending of spacetime. If this is the case, all matter bends spacetime to some degree. The more massive something is, the more spacetime will be bent and the more "gravity" will be experienced.

Could it then be said that, for example, if we stand near a massive (in the sense of containing lots of mass) building we will weigh more than if we did not (assuming weight as in the force)? Assuming and disregarding that the difference in weight could be almost negligible? If this is true, then I believe I can somewhat confirm my understanding of GR/SR.

• This question is best discussed in the framework of Newtonian gravity, as the involved energy densities are small. And the answer is yes. You can even measure distortion of earth's gravity near a mountain! So if you see this effect in the Newtonian limit, of course it carries over to GR. Commented May 19, 2015 at 21:13
• When standing in a tunnel inside a mountain... You weigh less! Woaa! The word "weigh" needs a definition. Commented May 19, 2015 at 22:54
• Considering that the building's center of gravity is probably above our head the vertical component of its gravity force will be pointing upwards, so we will "weigh" less. With the building replaced by the Moon this is quite visibly "felt" by water during the tides. Commented May 19, 2015 at 22:55