# Maximum range of projectile launched from an inclined plane [closed]

As we already know the max range if we launch it from any flat surface or from any height but I was wondering what will be maximum range if we launch it from inclined plane.

I have made on figure of what I observed:

Where alpha is angle from inclined plane and beta be the angle from which the projectile is launched.

• possible duplicate of The trajectory of a projectile launched from a hilltop - although the dupe has the inverse trajectory (throwing downhill instead of uphill) the approach is identical. Note that the answer gives a hint to solving the math - most of the math is given in that question. – Floris May 10 '15 at 19:15

This, in fact, is not too different from the flat surface case, the difference lies only in the distribution of the force components along the '$x$ and $y$' components of velocity.
In the flat surface projection case, you have acceleration only along the vertical direction. The given case can be converted to a non-inclined plane case by mentally rotating the system clockwise by $\alpha$ degrees. The only difference this would give you is in the two acceleration components, ($(a_x,a_y)=(-gsin\alpha,-gcos\alpha)$), which implies that both the $x$ and $y$ components of velocity would be affected by the gravitational force, unlike only the vertical component of velocity in the flat surface case. You can obtain a range expression like you did for the flat surface case.