# If an electron tunnels and loses amplitude, but maintains energy; where does the rest of the amplitude go?

I'm assuming the 'amplitude' is kind of like the MeV it has on it, so could be seen as a product of the voltage applied to that electron in a field.

But how can it 'lose' volts when passing the barrier, but still have the same energy as a whole? Does it increase the frequency in proportion to the voltage decrease?

• The amplitude of the wave function is just what gives you the probability of to find the electron at that position. I don't understand what you want to know. May 2, 2015 at 19:41
• The amplitude is not "kind of like MeV"... It is the probability amplitude. physics.stackexchange.com/questions/57595/… ..Or just google for it. May 2, 2015 at 19:43
• The probability of it tunneling is proportional to the energy of the tunneling electron in relation to the barrier. So why does the amplitude decrease, and yet energy remains constant? May 2, 2015 at 19:45
• The probability of tunneling is a different issue. The amplitude here refers to the probability of finding the electron, no matter what its energy, at a certain point. Low amplitude means that it's less likely to find the electron in that region. This decreased likeliness to find the electron is not related to the energy of the electron. May 2, 2015 at 19:51