Paramagnetic/ferromagnetic transition under a magnetic field The paramagnetic/ferromagnetic phase transition is an archetypal example of a continuous (or second-order) phase transition. When the temperature $T$ approaches the Curie temperature $T_c$, the magnetization $M(T)$, which is the order parameter of the transition, continuously goes to zero.
I heard (in an informal context) that under a constant nonzero magnetic field $H$, the transition becomes first order, but I was not able to find references which clearly confirm or infirm this statement, and I am not convinced of any of the possibilities.
So my question is : is the paramagnetic/ferromagnetic transition under magnetic field, $H\neq 0$, a continuous or a first order transition ? (It would be better with a reference, but I would also like an explanation.)
Thanks in advance.
 A: 
I heard (in an informal context) that under a constant nonzero magnetic field $H$, the transition becomes first order, but I was not able to find references which clearly confirm or infirm this statement, and I am not convinced of any of the possibilities.

It doesn't work like this. At temperature $T<T_c$, where $T_c$ is the critical temperature, you have a first order phase transition in $H$ when crossing the $H=0$ line. This is due to the fact that the magnetization $M$ develops a jump discontinuity at $H=0$ for $T<T_c$. You can see this in the mean-field approximation by considering the self-consistent equation for the magnetization,
$$M = \tanh(\beta (H + 2D M))$$
where $D$ is the number of spatial dimensions of the model.
This becomes clearer when visualizing the function $M(H,T)$ (picture from Introduction to the Theory of Soft Matter: From Ideal Gases to Liquid Crystals by Jonathan V. Selinger):

If you follow the blue line, keeping $H$ fixed at $H=0$ and changing $T$, you will encounter a transition at $T=T_c$. During this transition, the order parameter $M$ remains continuous, while its derivative with respect to temperature, $\partial M/\partial T$, changes discontinuously. Therefore, the transition is second order.
If you follow the red line, keeping $T$ fixed at $T<T_c$, you will encounter a phase transition at $H=0$: this time, $M$ has a jump discontinuity, i.e.
$$\lim_{H\to 0} \frac{\partial M}{\partial H} = \infty$$
Therefore, we are dealing with a first order phase transition.
A: The Landau model for ferromagnetism has the following expression for the free energy density, as a function of temperature $T$ and magnetization $M$:
$$F(T,M)=F_0(T)+\dfrac{a}{2}(T-T_C)M^2+\dfrac{b}{4}M^4+\dfrac{c}{6}M^6+\mathcal{O}(M^6)$$
First order phase transition occurs when the first derivative of $F$ (namely, the entropy) is discontinuous as $T\to T_C$, which happens in the case of a non-vanishing external magnetic field, represented by $b<0$. The stable minimum of $F$, for $T<T_C$ (and $T\sim T_c$) is:
$$M_0^2=\dfrac{|b|}{2c}\left(1+\sqrt{1-\dfrac{4ac}{b^2}(T-T_C)}\right)\simeq\dfrac{|b|}{c}+\dfrac{a}{|b|}(T_C-T)$$
The first order phase transition, at $T=T_C$, is thus characterized by the discontinuity $\dfrac{|b|}{c}$ in the order parameter, which is reflected in the entropy:
$$S=-\left(\dfrac{\partial F}{\partial T}\right)_M=-\dfrac{dF_0}{dT}-\dfrac{a}{2}M^2$$
$$\lim_{T\to T_C}\left[S_{T<T_C}-S_{T>T_C}\right]=-\dfrac{a|b|}{2c}$$
A: Maybe it is too late, but look at this lecture http://www.tcm.phy.cam.ac.uk/~bds10/phase/introduction.pdf

Fig. 1.3 (c)
When you change the magnetic field H at constant temperature T at $b^{'}$ the system in the spin-up state. Then you move to point $c^{'}$ at phase diagram and the system jumps discontinuity at spin-down state. So you have a first order phase transition. 
