2
$\begingroup$

Consider a particle of charge $q$ moving at velocity, $v$, enters a magnetic field $B$ which is perpendicular to its motion.

Now consider two observers, one stationary and the other moving at the same velocity, $v$.

The stationary observer, notices a force, $\vec{F}= q(\vec{v} \times \vec{B})$ which deflects the charge and makes it go in a circle.

For the moving observer, the charge is stationary, so it observes no force. However, the magnetic field moves in (changing magnetic field?). I can not figure out what equation to apply. Any thoughts.

Note: I am just curious, this is not a homework question

$\endgroup$
2
$\begingroup$

The electric and magnetic fields transform like a second rank tensor not a four vector. I would suggest you look in Jackson classical Electrodynamics for the transformations. One observer will see a moving magnetic field which will have an electric field component. At low velocity this will just be interpreted as magnetic induction.

| cite | improve this answer | |
$\endgroup$
  • 1
    $\begingroup$ It might be useful to paraphrase the relevant section of Jackson to show the case, rather than directing someone to a book that they may not possess. $\endgroup$ – Kyle Kanos Apr 27 '15 at 1:43

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.