# Physics behind this drunken ball

I am trying to understand the physics behind this drunken ball:

There is a wight inside the ball as he mentions, but where, at what position ?

http://www.grand-illusions.com/acatalog/Drunken-Ball-661.html

I took one plastic ball, punctured, and put 25% volume of water. It was behaving some what similar to this but not as drunken as shown here.

So my quick question is what is the physics behind this drunken ball, and where is the weight placed in the ball. (I would like to make one drunken ball ).

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Albert Falck 1 month ago
its just a Little heavier ball inside of the wooden ball. That's it.
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Devin McLeod 1 month ago
No that's not it...
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Albert Falck 1 month ago
the ball is pretty near an edge of the ball, not in the middle

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hompalai 6 months ago
U can make a similar one with a plastic ball. Fill half of it with sirup, and place a middle sized marble/iron ball inside.

• I suppose the mass distribution would have to be towards the edges of the ball. (Not uniformly, though.) The water you used inside the ball is dynamic, whereas an ordinary solid mass distribution is stationary, and that is why the ball you made isn't the same kind of "drunk" as the other one! – Hritik Narayan Apr 21 '15 at 12:36
• @HritikNarayan What do you mean by edges ? ball is symmetrical – gpuguy Apr 21 '15 at 12:40
• By edges I meant areas which are closer to the surface of the ball than to the center. (Sorry, I think edge shouldn't have been the word to use.) – Hritik Narayan Apr 21 '15 at 12:45
• OK. Then I will try to recreate this and post here. Thanks for the pointers. – gpuguy Apr 21 '15 at 12:59