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Having searched around I came to the conclusion that the electric field on the surface of a charged conductor is undefined as in there is a discontinuity but is there a way to explain it intuitively without the use of complex formulas? I have been unable to comprehend the answers to similar questions on this site.

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  • $\begingroup$ Did you see this answer to a similar question? Does that clear things up for you? $\endgroup$
    – Floris
    Apr 21, 2015 at 14:14
  • $\begingroup$ Well having read it I have the same question - if The transition from zero to finite electric field takes place at a point right where the surface of conductor shell starts. So where is the discontinuity and why is it there. $\endgroup$
    – PdX
    Apr 23, 2015 at 17:35

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