What is the lower limit value to the electric force between two charges separated by a fixed distance?
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1$\begingroup$ if you asking what is force between 2 charges separated by infinite distance, I may refer you to see the inverse square law $\endgroup$– user6760Commented Apr 20, 2015 at 5:43
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$\begingroup$ Are you asking how low the force can get if you reduce the charges? If so see Mohammad's answer. $\endgroup$– John RennieCommented Apr 20, 2015 at 6:07
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3$\begingroup$ Maybe he thinks of something like the minimal value in the sense of a quant of force, just like we can say that energy quant is $h\nu$. $\endgroup$– WalyKuCommented Apr 20, 2015 at 8:41
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$\begingroup$ @JohnRennie where is it? $\endgroup$– user541396Commented Jun 11, 2019 at 5:11
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$\begingroup$ @user541396 this answer. I think the user name has changed since I posted my previous comment. $\endgroup$– John RennieCommented Jun 11, 2019 at 5:20
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3 Answers
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If the charges are kept at a fixed distance R, the force will be given by:
$$ F = \frac{kQ_1Q_2}{r^2} $$
The smallest possible charge that can exist freely is that of an electron or proton which is numerically equal to $1.6 \times 10^{-19}$ coulomb, put the values in the equation and you get the answer.
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There is no range of electric force values, F = k*q/r^2 It will be fixed unless you having a mechanism that makes the charges to vary as required.
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The formula for electric force is given by $F = k \dfrac{q_1q_2}{r^2}$
Where $q_1$ and $q_2$ are the charges, and $r$ is the distance. Therefore, there is no lower limit. It is always given by this formula.
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$\begingroup$ Well charge is always quantized. So no. Charge is always in integral multiple of charge of electron. $\endgroup$ Commented Jun 11, 2019 at 5:10