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I came across this statement while studying electric currents and I am confused:

"There is no electric field inside a conductor. Hence no current can flow through it".

Is there a fallacy in this statement?

Any help would be appreciated.

The conductor being discussed is ideal. What is the driving force for the current in this case?

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  • $\begingroup$ In an electric current carrying wire the field inside the wire core is known to be E≠0. This is also the reason why you have a charge current inside the wire. E=0 inside the wire is only for electrostatics where a conductor is placed inside an electrostatic field but the conductor is not connected to a voltage source and is therefore not currying any current. $\endgroup$
    – Markoul11
    Commented Jun 11, 2021 at 10:03

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Is there a fallacy in this statement?

At least two.

First, unless one is referring to a perfect (ideal, etc.) conductor, only in the electrostatic case does the electric field inside a conductor vanish.

Second, in the case of an ideal conductor, there can be a steady current through without an electric field inside. Recall that an electric field accelerates electric charge. For a steady current without dissipation, no electric field is required to sustain the current.

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You could answer this question easily by a simple "back of the enveloppe" calculation.

Assume you have a plate of metal, say iron. Assume you displace all the free electrons from a 1-atom-thickness on one side to the other side. Calculate the charge densities on the surfaces. Calculate the electric field inside the plate.

I expect you to find an enormous electric field. This means that the reaction of a conductor to real-life electric fields should only involve a tiny fraction of the charge available in a thin 1-atom layer of iron. This means that the depletion of free electrons would affect the physics of conductors only in extreme-extreme conditions. Enormous forces would be at play and the material would probably explode.

I expect this result because it is known that the "Coulomb" is an enourmous electrical charge and that it corresponds to the charge of less than a mole of electrons (1E-5 moles actually).

In other words: real life electric fields and voltages are always created by a very small fraction of the available electrons.

Still other words: electric fields in laboratories are always very small compared to electric fields on the atomic scale, really very small.

Why is this so? Simply because materials are are "assembled" by electrical forces. Experiences in electrostatics rarely stress a material very much, specially dense materials. There are exceptions: disruptions in gases,

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  • $\begingroup$ I don't think you understood the question. The question is that if there is no electric field inside a wire, then why do electrons move from one end to the other. $\endgroup$
    – Tabish Mir
    Commented Apr 11, 2015 at 10:45

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