What if a twin is in a rocket in a synchronous orbit with the equator of the Earth while the second twin is standing at the equator watching his twin in space. If we use 0.87c for ease of calculation then the orbit needs only be about 1/3 of a light year out. All frames of reference being equal, the twins would have to think they are stationary to each other though one is traveling at 0.87c. How would this theory play out then? Even their light clocks would appear the same. Now place another non-rotating observer at the North Pole observing the twins and a real paradox develops. Since the twins experience the same referential frame they would see each other age the same. The North Pole observer should witness a 2:1 ratio between them. Run it for ten years and then have all three stand together and argue over which of the twins is older. Solutions?
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$\begingroup$ See Is gravitational time dilation different from other forms of time dilation? and Can a ultracentrifuge be used to test general relativity? for an explanation of how motion in a circle causes time dilation. I don't think either of these counts as a duplicate, but they essentially answer your question. $\endgroup$– John RennieCommented Apr 10, 2015 at 10:27
2 Answers
All frames of reference being equal,
All frames of reference are not equal and, in this case, they're especially unequal. If my calculation is correct, for the rocket to travel around Earth at $0.87c$ at a distance of 1/3 light-year requires a proper inward acceleration of about $2,669\,\mathrm g$. The twin on the Earth has a proper acceleration of about $1\mathrm g$.
A result from special relativity is that accelerated clocks run slower than unaccelerated clocks.
From the Wikipedia article "Time Dilation":
From the local frame of reference (the blue clock), a relatively accelerated (e.g. red) clock moves more slowly
They are not stationary relative to each other. One twin is being constantly accelerated towards the other to remain in orbit. A rotating reference frame is not an inertial reference frame, so General Relativity is required to understand what is happening.
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3$\begingroup$ I don't believe this requires GR to understand; SR can handle accelerated reference frames and we can pose this problem in a flat spacetime. $\endgroup$ Commented Apr 10, 2015 at 0:46
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2$\begingroup$ No GR isn't required. See Can a ultracentrifuge be used to test general relativity?. I wish we could knock this canard on the head. $\endgroup$ Commented Apr 10, 2015 at 10:24