6
$\begingroup$

On BBC episode The Secrets of Quantum Physics (Part 1) Jim Al-Khalili explains quantum mechanics for the layman. In the first half, he does a very good job; in the second half, either he thought his explanations/analogies were clear but were not, or I terribly missed something. Here is a summary of the part on “entanglement”.

Let me try and explain this by imagining the two particles are spinning coins. Imagine these coins are two electrons created from the same event and then moved apart from each other. Quantum mechanics says that, because they're created together, they're entangled. And now many of their properties are for ever linked, wherever they are. The Copenhagen interpretation says that until you measure one of the coins, neither of them is heads or tails. In fact, heads and tails don't even exist. And here's where entanglement makes this weird situation even weirder. When we stop the first coin and it becomes heads; because the coins are linked through entanglement, the second coin will simultaneously become tails. And here's the crucial thing: I can't predict what the outcome of my measurement will be, only that they will always be opposite. Einstein believed there was a simpler interpretation: Quantum particles were nothing like spinning coins; they were more like, say, a pair of gloves, left and right, separated into boxes. We don't know which box contains which glove until we open one, but when we do, and find, say, a right-handed glove, immediately, we know that the other box contains the left-handed glove.

[To compare these two theories, Jim Al-Khalili devises a semi-analogous card game.]

The card game is against a mysterious quantum dealer. The cards he deals represent any subatomic particles, or even quanta of light, photons. And the game we'll play will ultimately tell us whether Einstein or Bohr was right. Now, the rules of the game are deceptively simple. The dealer's going to deal two cards face down: If they're the same color, I win; if they're different colors, I lose.

[He loses each game.]

I know what the dealer's doing here. ,Clearly, the deck has been rigged in advance so that every pair came out as opposite colors. But there's a simple way to catch the dealer out. So what we can do now is change the rules of the game. This time, if they are the opposite color, I win.

[He loses each game.]

I'm now not going to tell the dealer which game I want to play, same colors wins, or different color wins, until after he's dealt the cards. Now, because he can never predict which rules I'm going to play by, he can never stack the deck correctly. Now he can't win...or can he? This gets to the very heart of Bell's idea. If we now start playing and I win as many as I lose, then Einstein was right. The dealer is just a trickster with a gift for slight of hand.

[He loses each game.]

Assuming that the analogy is correct (who am I to judge him), how does the third card game relate to the Einstein-Bohr debate? Specifically, his conclusion, “This gets to the very heart of Bell's idea. If we now start playing and I win as many as I lose, then Einstein was right”.

Continuing, Jim Al-Khalili performs an experiment, which supposedly proves that Bell's Equation was right. Is there a nontechnical explanation of how the truthfulness of Bell's inequality confirms/proves Bohr's interpretation on “entanglement”?

$\endgroup$
  • $\begingroup$ Hi either he thought his explanations/analogies were clear but were not, or I terribly missed something I saw his "explanations" and I think you did not miss anything, it was just an off day for him on that show. He completely lost me too. They should have edited it out and tried another analogy, imo ....regards $\endgroup$ – user74893 Apr 8 '15 at 21:16
  • $\begingroup$ @blackened Could you clarify what you do understand, and what you don't understand about this example? It sounds like you are having trouble seeing the connection between the card game and Bell's experiment, but I just want to be sure. $\endgroup$ – Eriek Apr 8 '15 at 22:22
  • $\begingroup$ @user154879 yeah, sure I would probably agree with you on that , but the problem remains that BBC program was targeted at the 99 odd % of the people watching in the UK & Ireland who are not at that level, (including myself), so in that sense, imo it was a bad analogy. regards $\endgroup$ – user74893 Apr 8 '15 at 22:24
  • $\begingroup$ @irish physics Forgot @ tag, question was meant for OP. $\endgroup$ – Eriek Apr 8 '15 at 22:26
  • 1
    $\begingroup$ The part were he says "their properties are for ever linked" is wrong. Its that they are in a state of have a relationship of properties rather than having the properties, once you make one of them have a property you make the other have the corresponding property, the relationship they used to have is now expressed and you can now change either one without affecting the other. $\endgroup$ – Timaeus Jun 16 '15 at 15:39
1
$\begingroup$

Bells inequality doesn't prove that Bell or Einstein are right, it only shows (mathematically) that there is a difference (an inequality) in the predicted outcomes of Quantum Mechanics and Classical Mechanics even before an experiment is done. Classical mechanics relies on local hidden variables and Quantum mechanics more on Spooky action at a distance so to say. Bell's theorem on the other hand states that no real or physical local hidden variable theory can reproduce all the predictions of quantum mechanics. The third card game is an analogy to represent some of the actual experiments where two entangled particle (which are very hard to produce) are tested for correlation. Two entangled photons fired are at two separate detectors but along the way they go through a slit that can be set in three different positions 120 degrees apart. The photons will (Y) or will not (N) go through the slits. Bell's theory was that no matter how you set the slit settings there will only be eight different outcomes. Depending on the photon and the settings the photon may not go through (theoretically) any of the slits NNN or all of the slits YYY. Then there are six other combinations of NNY, NYN, NYY, YNY, YYN, or YNN. The other entangled photon at the other detector has the same odds and when you compare the outcomes Bell's math claims that the matching corelation will be no more than 33%. On the other hand quantum mechanics experiments test 25%. Sorry I may be off on the way I'm remembering the percentages but I think that's the basics.

$\endgroup$
0
$\begingroup$

I just watched the video and here is my understanding.

First the card game is just an analogy, which is not literally a physical phenomenon. Once this being understood, we can go ahead to see how each part of the game corresponds to that in the Bohr-Einstein debate, the so-called EPR "entanglement game".

In the EPR entanglement, there are a pair of particles, correlated to each other by the initial interaction. Because of the random nature of the system, each particle could be found in either of the two states: up or down. But the states of each pair of particles are fully correlated. The moment when the particle 1 is found to be up, the particle 2 is down. Vice versa, the particle 1 down and the particle 2 up.

There must be some underlying model of the unseen nature to explain what was observed, namely, the correlation between the two particles in each pair. The card game corresponds to the experiment for determining which model might explain what was observed. The first two card games corresponds to the two possible combinations described above, namely,

  1. particle 1 up and particle 2 down
  2. particle 2 down and particle 1 up

Here the Jim/two-card correspond to particle 1/2. The up/down corresponds to the same/different color. The dealer corresponds to the unseen nature. In these two games, what was observed could be easily explained by the initial rigging action of the dealer. This explanation corresponds to the Einstein's model, in which what was observed had been arranged in advance by the dealer/nature. In the Bohr's model, it states that the dealer hadn't rigged the deck in advance, the correlation always happened at the moment when Jim decided what to choose (the same or different color). Therefore the third game came into the play to check if the dealer had really fixed the cards in advance. If it had indeed done so, which would have proved Einstein was right. Otherwise, it would have proved Bohr was right. Surprisingly, Bohr was right, as shown in the video. It appeared that the dealer didn't fixed cards in advance. The correlation could only be explained as if it occurred the moment Jim decided what to choose.

The heart of the whole game analogy says that, the quantum correlation is much stronger than the classical correlation.

$\endgroup$
  • $\begingroup$ I should add that, the whole explanation in this answer was to reproduce what Jim was trying to teach in the video. I don't hold any of his opinions. I disagree with him on what the Bell's inequality really means. To explain why, that would inevitably involve careful and detailed technical presentations. $\endgroup$ – G. Xu Apr 10 '15 at 16:45
0
$\begingroup$

Let's say the particles in your first paragraph are pairs of photons, one of the choices the TV program considered. Then head means a photon is polarised in some given direction and tail in another given direction. We need two devices called analysers to measure each polarisation. One probes one photon and the other one the other photon. So now, in this card game analogy, the colour of the cards is a mashup of both the polarisation of the photons and the setting of those analysers, I think. So this makes it hard to precisely relate the games to real experiment. But I can still get the gist of the last game I think. It represent experiments where the settings of the analysers is changed while the photons are in flight.

This is done to defeat the possibility that card deck was rigged beforehand, since now the card dealer cannot predict the player choices, exactly as the mechanism producing the pairs of photons cannot know, or however the pair of photons change during their flight, it/they cannot know what the settings of the analysers will be when they get to them.

To really answer your last question, the game considered in the program is too confused, as I pointed out above. The example of the boxes with gloves they started with can be spun in a more satisfying way actually, and I don't understand why they did not pursue this course. I can do that later if you wish.

$\endgroup$
-1
$\begingroup$

It's funny how people keep saying "the Copenhagen Interpretation says such-an-such and that's really weird and makes no sense". Such an embarrassing string of bad explanations really ought to make one think twice about accepting it as an explanation.

There is NOTHING in the equations which says the wavefunction collapses, that's a superfluous idea added by confused physicists in the 1920s and we're still chucking it around. Macroscopic decoherence is the simple, straightforward coherent explanation.

In this picture, the dealer with the cards analogy breaks down completely -- it can't translate and still remain intact.

Going back to a real phyiscal example. Suppose you have two particles created in an entangled state. One is "spin up" and one is "spin down" but you don't know which is which. Here's what happens, the initial situation is that the following statements are both simultaneously true:

1) A is spin-up and B is spin-down.

2) B is spin-up and A is spin-down.

This is your superposition of states. Then you perform an observation of the spin of particle A. The following statements are then both simultaneously true.

1) A is spin-up and B is spin-down and you observe "A is spin-up."

2) B is spin-up and A is spin-down and you observe "A is spin-down."

The states are still superposed, see?

Later you observe the spin of particle B. The following statements are then both simultaneously true.

1) A is spin-up and B is spin-down and you observe "A is spin-up" and you observe "B is spin down".

2) B is spin-up and A is spin-down and you observe "A is spin-down" and you observe "B is spin-up."

The wavefunction of the whole universe contains both outcomes in their entirety, at least that's what the equations say. When you complain "but I only observe A is spin-up, not A is spin-down" what you are observing is which part of the wavefunction "you" are in.

The only problem is understanding what the word "you" means in this description.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.