1
$\begingroup$

First of all, I am not a physicist. I'm a graduate math student and recently I came across the concept of T-duality. Actually I'm studying generalized complex geometry, which according to this paper (Generalized complex geometry and T-duality) can be used to get some nice interpretations of T-duality.

After reading some of it, I thought the "T" stand for torus, because the the fiber are torus. But then I found another paper (Spherical T-duality) defining T-duality for $SU(2)$-bundles. At first I asked myself "Why keep calling it T-duality, if the fiber are not torus anymore?" Probably it means something else...

So, what does the "T" stand for in T-duality?

$\endgroup$
3
$\begingroup$

The name T-duality stands for Target-space duality, see e.g. this preprint.

$\endgroup$
2
$\begingroup$

T duality and S duality come from the $T$ transformation and $S$ transformation which generate the modular group $PSL(2,\mathbb{Z})$.

$\endgroup$
1
$\begingroup$

It comes from S matrix theory, long before quarks were imagined, S,T and U characterize the type of exchange in the Feynman diagrams entering the S matrix calculation, and they are called Mandelstam variables.

s channel t channel u channel

s channel-------------------------- t channel------------------------u channel

duality meant that the sums could be done either in S channel or T channel and the result should be the same.

There is a resurrection of the scattering matrix for strings and I guess the definition has morphed to what you find in the link you gave.

It is also used in nuclear physics, where dualities are useful.

The above is history of theory in particle physics, and it was T because it came after the S of Scattering ( like y after x).

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.