Potential difference = Current x Resistance where Resistance is a constant. Walking through a circuit I have 1 battery, a wire and 2 components. I start of with 6 volts at the battery and after the current goes through the 2 components I'm left with a 0 volts.
My problem is understand this statement:
when an electrical charge goes through a change in potential difference then energy is transferred. Now, I'm trying to put this statement into the circuit described above.
I start of with a resistance of 1 ohm by the wire and 6 amperes which result in 6 volts. When I meet the resistor however the resistance increases to let's say 3. Does the current decrease at the same rate the resistance increases? So if the resistance goes down to 3 will the current be 2 so that in the end I have a potential difference of 6? If that's the case then why am I loosing 3 volts after the first component since there is no change in potential difference.
I guess my question can be shortened to whether or not the current decreases at the same rate resistance increases and vice-versa?
I'm pretty sure my question is not so well but here is the circuit described:
Is there any way you can walk me through what happens here? How does this relate to ohm's law?