A weight "m" is suspended from the center of a light, taut and originally horizontal rope. After suspending the weight "m", what angle must the rope make with the horizontal if the tension in the rope is to equal the weight "m"?
Here is what I have so far.
I'm not sure what to do from here on out. I'm assuming T1 and T2 will be equal and i'm also assuming that T1 and T2 have about half the mass of M. So is the idea to solve for M then substitute I'm guessing but when I did that i ended up with something like 2sin(theta)=sin(theta).