-2
$\begingroup$

An object travels 11 m north and then turns around and travels 25 m south. If the total time of travel is 52 s what is the average speed and velocity of the object.

I used the formula I was told

average speed = distance/time

11+25m= 36m

36m/52 s = 0.692 s is the answer I calculated but my textbook says its 36/52 s = 9/13

average velocity = displacement/time

11-25=14m

14m/52 s = 0.269 s is the answer I calculated but its still wrong

14m/52 s = 7/26 is the answer

Can someone please tell me what I'm doing wrong

$\endgroup$

closed as off-topic by Pranav Hosangadi, JamalS, John Rennie, ACuriousMind, Qmechanic Mar 21 '15 at 14:34

This question appears to be off-topic. The users who voted to close gave this specific reason:

  • "Homework-like questions should ask about a specific physics concept and show some effort to work through the problem. We want our questions to be useful to the broader community, and to future users. See our meta site for more guidance on how to edit your question to make it better" – Pranav Hosangadi, JamalS, John Rennie, ACuriousMind, Qmechanic
If this question can be reworded to fit the rules in the help center, please edit the question.

  • $\begingroup$ Learn to do some math without the calculator. Seriously. You'll be better for it. $\endgroup$ – Bill N Mar 21 '15 at 3:52
  • $\begingroup$ I wasn't told to find the answer without a calculator. $\endgroup$ – Moon CrawlerVG Mar 21 '15 at 20:49
1
$\begingroup$

The problem is that 9/13 is approximately 0.692. You used decimals, the book used fractions.

$\endgroup$

Not the answer you're looking for? Browse other questions tagged or ask your own question.