May be $f(\vec{x}), \vec{g}(\vec{x})$ an arbitrary functions dependent on the coordinates $\vec{x}=(x,y,z)^T$. Defining the following function dependent on a 3-dimensional curve $\vec{\gamma(t)}$ parametrized by $t \in [0,1]$:

$S := \int_{R^3}\int_{R^3} (f(\vec{x})exp(\int_0^1 \vec{g}(\vec{\gamma(t)}) \vec{\gamma'(t)}dt)f(\vec{x'}))d^3x d^3x'$.

It was defined $\vec{x}=\vec{\gamma(0)}, \vec{x'}=\vec{\gamma(1)}$ and it was integrated over all possible endpoints of the curve $\vec{\gamma(t)}$. How I can compute

$I := \int Sd[\vec{\gamma(t)}]$ ($[\vec{\gamma(t)}]$ denotes that every possible path with endpoints $\vec{x}, \vec{x'}$ that is connected must be integrated up)?

This Integration is similar to Feynman's path-integral over all possible paths in Quantum field theory. The exponential I can expand into a taylor series, but how can I evaluate the products $\int \vec{\gamma'(t_1)} \otimes ... \otimes \vec{\gamma'(t_n)}d[\vec{\gamma(t)}]$ where every $\vec{\gamma(t_i)},i \in \{ 1,...,n \}$ has the same endpoints (there occur both open and closed paths)?

Every help would be greatly appreciated.

  • $\begingroup$ Are you aware that we, in general, don't really compute the path integral? $\endgroup$ – ACuriousMind Mar 9 '15 at 21:27
  • $\begingroup$ I am asking about integrating over a dyadic product of Tangent vectors. $\endgroup$ – kryomaxim Mar 9 '15 at 21:57

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.