# Interpretation of vector mesons in QCD

It is well-known that scalar mesons are interpreted as pseudogoldstone bosons which is connected with spontaneous broken $SU(3) \times SU(3)$ symmetry to $SU(3) \times SU(3) / SU(3)_{chiral}$.

Is there similar explanation for vector mesons? I understand that broken symmetry corresponds to existense of particles with spin zero, but I expect that vector mesons can also be explained through something like that, because they correspond to irreducible representation of $SU(3)$ group (as well as scalar mesons).

• Since physicists are very sloppy with this - do you mean $\otimes$ or $\times$, i.e. the tensor product or the direct product of groups? (I heavily suspect it is $\times$) Commented Mar 9, 2015 at 12:43
• A good reference for this (maybe not the best, just the one I know about) is in the introductory chapter of Manohar and Wise's textbook on heavy quark physics. Granted, this is presented as a review for someone who's familiar with it (which I am not), and I've been hoping to find a more detailed explanation. Commented Mar 9, 2015 at 12:55
• @ACuriousMind : I meaned direct product (I thought that $\otimes$ denotes direct product). Commented Mar 9, 2015 at 13:20
• @jwimberley : Where exactly can I find information about vector mesons in this chapter? Commented Mar 9, 2015 at 14:39
• @AndrewMcAddams You can't, because I was wrong! Sorry for the red herring. A later chapter does talk about the mass splitting between the spin 1 D* and B* mesons relative to the spin 0 D and B mesons, which is derived in the heavy quark limit and isn't general. I'd confused this with the introductory section 1.4, which just covers chiral symmetry breaking and the masses of spin-0 mesons. Commented Mar 9, 2015 at 15:10