What meaning/use is associated with the notion of proper length in general relativity? Do you know an example of any quantity that depends on it? I have so far found statements like "the length corresponding to a proper time between two measurement events", or "the length as measured by some observer". However, neither of these ideas seem to work.
For example, if I want to measure the distance from myself to an object, I could do so by bouncing a photon from it and counting my proper time between firing the photon and receiving it. We can do this in the radial direction of the Schwarzschild metric, for example, using Eddington–Finkelstein coordinates (outside of the event horizon, of course). The resulting length (EDIT: derivation at the bottom of this question) depends on the difference in tortoise coordinates, i.e. $$L_\text{measured} = \frac{c \, \tau_\text{Round Trip}}{2} = \sqrt{f(r_\text{observer})} \,\, [r^{*}(r_\text{object}) - r^{*}(r_\text{observer})] $$ where
$r^{*}(r) = r + r_{s} \ln (\frac{r}{r_{s}} - 1)$ is the tortoise coordinate,
$f(r) = 1-\frac{r_{s}}{r}$ relates proper time (squared) to coordinate time (squared),
and $r_{s}$ is the Schwarzschild radius. This isn't the proper length between observer and object, which is given by integrating $\mathrm{d}S^{2}$ from $r_{observer}$ to $r_{object}$, with $\mathrm{d}t=\mathrm{d}\theta=\mathrm{d}\phi=0$: $$ L_\text{prop} = \Big[ r\sqrt{f(r)} + \frac{r_s}{2} \ln \big( r\sqrt{f(r)} + r - \frac{r_{s}}{2} \big) \Big]^{r=r_\text{object}}_{r=r_\text{observer}} $$
Unless I'm mistaken, these two expressions aren't the same, despite some superficial similarity.
So the proper length doesn't give the distance measured, and it isn't a distance corresponding to the propagation time of light/information from one point to another. So what exactly is it?
I realise that by fixing the observer and object radii, I'm assuming each has some nonzero proper acceleration... is that the source of the discrepancy?
Questions very similar to this one have been asked before, but the answers have either discussed flat space (this one), or have resolved different but related conceptual issues (such as this one, and this extremely interesting answer).
EDIT: For clarity I'll include my derivation of the measured length.
Eddington-Finklestein coordinates $(u,v)$ are defined by: $$u=ct-r^{*} \,\,\, \text{and} \,\,\, v=ct+r^{*}$$ Radial null geodesics in the Schwarzschild metric correspond to $u=$constant (outgoing rays) and $v=$constant (uncoming rays). Now, letting $r_{observer}<r_{object}$ and taking the photon to be emitted at $t=0$, we have, for the outward trip: $$ u = 0 - r^{*}(r_\text{observer}) = c t_\text{reflected} - r^{*}(r_\text{object})$$ i.e. $ct_\text{reflected} = r^{*}(r_\text{object})-r^{*}(r_\text{observer})$
Now for the return trip, we have $$ v= ct_\text{reflected} + r^{*}(r_\text{object}) = ct_\text{RoundTrip} + r^{*}(r_\text{observer}) $$ i.e. $ct_\text{RoundTrip} = ct_\text{reflected} + r^{*}(r_\text{object}) - r^{*}(r_\text{observer}) = 2[r^{*}(r_\text{object}) - r^{*}(r_\text{observer})] $
putting this in terms of the proper time of the observer, we have $$c \tau_\text{RoundTrip} = \sqrt{f(r_\text{observer})} c t_\text{RoundTrip} = 2 \sqrt{f(r_\text{observer})} [r^{*}(r_\text{object}) - r^{*}(r_\text{observer})] $$ which we divide by two to get the distance, because we know the photon went there and back.